Best of Internet : A collection of softwares and extensions

This is a collection of softwares and extensions.

  • 7-Zip : 7-Zip is an open source file archiver with a high compression ratio. My favourite.
    OS: Windows, Linux.
  • Firefox : An opensource browser concerning about the privacy.
    OS: Windows, Linux, Android, OS X.
  • MPC-HC : Media Player Classic - Home Cinema is an extremely light-weight media player for Windows. This media player is twice as efficient as VLC Media Player.
    OS: Windows.
  • qBittorrent : An advanced and multi-platform BitTorrent client with a nice Qt user interface as well as a Web UI for remote control and an integrated search engine. qBittorrent aims to meet the needs of most users while using as little CPU and memory as possible.
    OS: Windows, Linux, Mac OS X, OS/2, FreeBSD
  • VLC Media Player :VLC is a free and open source cross-platform multimedia player and framework that plays most multimedia files as well as DVDs, Audio CDs, VCDs, and various streaming protocols.
    OS: Windows, Linux, Android.

ECE 1.1: Level 3.5 - Recursion


Recursion simply means self reference. In programming we usually call a function from itself. Recursion is a very powerful method of solving problems.


Calculating factorial using recursion

Program to calculate factorial of a number by using recursion :


∇² = φ Doc

0.0 - Learning to Program - An Introduction

This is an introduction to programming.

0.1 - What is Programming?

This is an experomental piostsadd.

First Post

When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$ A Cross Product Formula \[\mathbf{V}_1 \times \mathbf{V}_2 = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ \frac{\partial X}{\partial u} & \frac{\partial Y}{\partial u} & 0 \\ \frac{\partial X}{\partial v} & \frac{\partial Y}{\partial v} & 0 \end{vmatrix} \]

Math in TeX notation

When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$ $$ \begin{array}{rcll} y & = & x^{2}+bx+c\\ & = & x^{2}+2\times\dfrac{b}{2}x+c\\ & = & \underbrace{x^{2}+2\times\dfrac{b}{2}x+\left(\frac{b}{2}\right)^{2}}- {\left(\dfrac{b}{2}\right)^{2}+c}\\ & & \qquad\left(x+{\dfrac{b}{2}}\right)^{2}\\ & = & \left(x+\dfrac{b}{2}\right)^{2}-\left(\dfrac{b}{2}\right)^{2}+c & \left|+\left({\dfrac{b}{2}}\right)^{2}-c\right.\\ y+\left(\dfrac{b}{2}\right)^{2}-c & = & \left(x+ \dfrac{b}{2}\right)^{2} & \left|\strut(\textrm{vertex form})\right.\\ y-y_{S} & = & (x-x_{S})^{2}\\ S(x_{S};y_{S}) & \,\textrm{or}\, & S\left(-\dfrac{b}{2};\,\left(\dfrac{b}{2}\right)^{2}-c\right) \end{array} $$ Experimental Post